Balance annihilation plane enchantment energy cost (#8590)

The current implementation had two problems:

Enchanting an annihilation plane with any level of efficiency (and
nothing else) would reduce the required energy to zero due to
multiplying with the 0 in levelSum directly.

Enchanting an annihilation plane with unbreaking would increase the
energy cost by a factor of 8 per level of unbreaking, but only leading
to an average saving of 50% (lv1), 33% (lv2), or 25% (lv3), effectively
increasing the average cost rather than reducing it.

Fixes #8188

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Co-authored-by: Sebastian Hartte <shartte@users.noreply.github.com>

Author: Mithi83

src/main/java/appeng/parts/automation/ItemPickupStrategy.java

@@ -270,9 +270,11 @@ protected float calculateEnergyUsage(ServerLevel level, BlockPos pos, List<ItemS
                 int randomNumber = level.getRandom().nextInt(unbreakingLevel + 1);
                 useEnergy = randomNumber == 0;
             }
+            // Increase energy usage 8x for each *other* enchantment that might affect the pickup.
+            // Ignore efficiency & unbreaking since we did account for them here explicitly.
             var levelSum = enchantments.entrySet().stream().map(Map.Entry::getValue).reduce(0, Integer::sum)
-                    - efficiencyLevel;
-            requiredEnergy *= 8 * levelSum * efficiencyFactor;
+                    - efficiencyLevel - unbreakingLevel;
+            requiredEnergy *= (levelSum > 0 ? 8 * levelSum : 1) * efficiencyFactor;
         }
 
         return useEnergy ? requiredEnergy : 0;