by Maciej Sikora @maciejsikora
For given function type Fn, and any type A (any in this context means we don't restrict the type, and I don't have in mind any type 😉) create a generic type which will take Fn as the first argument, A as the second, and will produce function type G which will be the same as Fn but with appended argument A as a last one.
For example,
type Fn = (a: number, b: string) => number
type Result = AppendArgument<Fn, boolean>
// expected be (a: number, b: string, x: boolean) => numberThis question is ported from the original article by @maciejsikora