When FAA0002, FAA0003 or FAA0004, also apply fix for FAA0001 if possible

[bkqc]

In multiple cases, once we use the autofix for FAA0002-4, we end up with a new FAA0001. Why not apply the fix at the same time if it is a better fix?
For instance,

Assert.IsTrue(modele.Journalisation.CritereRecherche.Any(x => x.StartsWith("Etat traitement")));

would, after FAA0003 auto fix, become

modele.Journalisation.CritereRecherche.Any(x => x.StartsWith("Etat traitement")).Should().BeTrue();

but create an FAA0001 whose fix would end up with

modele.Journalisation.CritereRecherche.Should().Contain(x => x.StartsWith("Etat traitement"));

which is way better.

[cbersch]

Yes, that would be better. Unfortunately, one cannot simply combine two diagnostics. The analyzer would need to analyze the code passed to Assert.IsTrue. I'll have to evaluate, how much refactoring this would be.