how to use replacements when using PowerShell in Windows

[huangjj27]

What version of ripgrep are you using?

> rg --version
ripgrep 13.0.0
-SIMD -AVX (compiled)
+SIMD +AVX (runtime)

How did you install ripgrep?

cargo install ripgrep

What operating system are you using ripgrep on?

Windows 10

Describe your bug.

What are the steps to reproduce the behavior?

here is the file.txt:

10a3789
51b7883

and then I run in PowerShell:

rg -N "^(\w+)$" file.txt -r "'$1',"

What is the actual behavior?

I get these lines:

'',
'',

but without the replacement, it captured:

> rg -N "^(\w+)$" file.txt                   
10a3789
51b7883

What is the expected behavior?

as I want to add a single quote both before and after each line, and then add a comma to end each line expecting it cat these lines:

'10a3789',
'51b7883',

[BurntSushi]

I can reproduce your problem:

$ rg -N '^(\w+)$' /tmp/file.txt -r "'$1',"
'',
'',

But this looks like a shell problem, not a ripgrep problem. In particular, single quotes have nothing to do with this. If you remove your single quotes, you should get the same behavior. In my shell, I have to use \$ to avoid having it interpreted as an environment variable:

$ rg -N '^(\w+)$' /tmp/file.txt -r "'\$1',"
'10a3789',
'51b7883',

Using just single quotes is possible too, although it is a bit unwieldy and I have no idea whether it works on Windows or not:

$ rg -N '^(\w+)$' /tmp/file.txt -r "'"'$1'"'"','
'10a3789',
'51b7883',

[huangjj27]

It seems neither of the commands works on Powershell:

> rg -N '^(\w+)$' file.txt -r "'\$1',"          
'\',
'\',
> rg -N '^(\w+)$' file.txt -r "'"'$1'"'"','  
$1: The system cannot find the file specified. (os error 2)
': The system cannot find the file specified. (os error 2)
,: The system cannot find the file specified. (os error 2)
file.txt
'
'

and I tried both of the commands in my WSL, both works:

$ rg -N '^(\w+)$' file.txt -r "'\$1',"
'10a3789',
'51b7883',
$ rg -N '^(\w+)$' file.txt -r "'"'$1'"'"','
'10a3789',
'51b7883',

hope these information will help others

[BillHally]

PowerShell uses a backtick character to prevent variable substitution in double-quoted strings, so the following will work:

rg -N '^(\w+)$' file.txt -r "'`$1',"

[huangjj27]

Here is another example. if my replacement string quoted by double quote marks, captures are missing:

> echo "2012-03-14, 2013-01-01 and 2014-07-05" | rg '(?P<y>\d{4})-(?P<m>\d{2})-(?P<d>\d{2})' --replace "$m/$d/$y"
//, // and //

but if they are quoted by single quote marks, variables are captured:

> echo "2012-03-14, 2013-01-01 and 2014-07-05" | rg '(?P<y>\d{4})-(?P<m>\d{2})-(?P<d>\d{2})' --replace '$m/$d/$y'
03/14/2012, 01/01/2013 and 07/05/2014

This may be a helpful walkaround when we don't contain single quote marks ' in our replacement.