How do you conditionally generate code?

[farhansolodev]

I want to generate code for every property of a class Foo except for Foo's methods. I am using $$propsOfType within repetitions to do this, but since that macro also returns the classes methods, I want to skip every run of a repetition where the property returned by $$propsOfType does not exist in Object.keys(Foo) since Object.keys does not return a classes methods, which is want I want.

To be clear, this:

    +[[$$propsOfType!<F>()], (prop) => {
        $$ts!(`${toVarName}.${prop} = ${fromVarName}.${prop}`)
    }];

generates this:

        this.prop1 = prop.prop1;
        this.prop2 = prop.prop2;
        this.prop3 = prop.prop3;
        this.prop420 = prop.prop420;
        this.prop1337 = prop.prop1337;
        this.someMethod = prop.someMethod; // dont want this

but I'd like to do something like:

    +[[$$propsOfType!<F>()], (prop) => {
        if (Object.keys(F).includes(prop)) { // just pseudocode, does not compile
        	$$ts!(`${toVarName}.${prop} = ${fromVarName}.${prop}`)
        }
    }];

to generate:

        this.prop1 = prop.prop1;
        this.prop2 = prop.prop2;
        this.prop3 = prop.prop3;
        this.prop420 = prop.prop420;
        this.prop1337 = prop.prop1337;
        // this.someMethod = prop.someMethod; // this is now not generated

[GoogleFeud]

Hi! You can do this with the $$typeMetadata built-in macro, which separates the object's properties and methods:

function $test<T>(toName: string, fromName: string) {
    +[[$$typeMetadata!<T>(true).properties], (prop: TypeMetadataProperty) => {
        $$ts!(`${toName}.${prop.name} = ${fromName}.${prop.name}`);
    }]
}

playground

[farhansolodev]

You sir are a legend!