Implement ExpantaNum function for number formatting

Author: MakiNishi3

notations/normal/ExpantaNum.js

@@ -0,0 +1,55 @@
+var notations=notations||{};
+notations.normal=notations.normal||{};
+notations.normal.ExpantaNum=(function (i){
+  if (!(i.isFinite())) return "Infinity";
+  if (i.lt(1000)) return i.toString();
+  if (i.gte(1000)&&i.lt(1e+6)){
+    var h=Number(i);
+    var l;
+    var r=Math.floor(h%1000);
+    l=String(r);
+    if (r<10) l="00"+l;
+    if ((r>=10)&&(r<100)) l="0"+l;
+    return Math.floor(h/1000)+","+l;
+  }
+  var numbernames=["thousand","million","billion","trillion","quadrillion","quintillion","sextillion","septillion","octillion","nonillion","decillion","undecillion","duodecillion","tredecillion","quattuordecillion","quindecillion","sexdecillion","septendecillion","octodecillion","novemdecillion"];
+  var namefragments=[["","un","duo","tre","quattuor","quinqua","se","septe","octo","nove"],["","deci","viginti","triginta","quadraginta","quinquaginta","sexaginta","septuaginta","octoginta","nonaginta"],["","centi","ducenti","trecenti","quadringenti","quingenti","sesgenti","septingenti","octingenti","nongenti"],["","milli","micro","nano","pico","femto","atto","zepto","yocto","xon","vec","mec","duec","trec","tetrec","pentec","hexec","heptec","octec","ennec"],["","mono","di","tri","tetra","penta","hexa","hepta","octa","nona"],["","vec","icosa","triaconta","tetraconta","pentaconta","hexaconta","heptaconta","octaconta","ennaconta","hecto","kilo","pentalogue","hexalogue","heptalogue","octalogue","ennalogue","dekalogue","generaltriplex",]];
+  var e=3*Math.floor(Number(Decimal.log10(i))/3);
+  var l=Math.floor(e/3)-1;
+  //console.log(l);
+  if (l<=19){
+    return Math.floor(Number(i.div(new Decimal("1e+"+e)))*1000)/1000+" "+numbernames[l];
+  }else{
+    var r="";
+    var s;
+    var mu;
+    for (var g=Math.floor(Math.log10(l)/3);g>=0;g--){
+      var mu=Math.floor(l/Math.pow(1000,g))%1000;
+      s="";
+      if ((mu===1)&&(g!==0)){
+        s="";
+      }else if ((mu<=19)&&(g===0)){
+        s=numbernames[mu];
+      }else{
+        var d=[mu%10,Math.floor(mu%100/10),Math.floor(mu/100)];
+        s=namefragments[0][d[0]];
+        if ([3,6].includes(d[0])&&(((d[1]!=0)&&[2,3,4,5].includes(d[1]))||((d[1]==0)&&[3,4].includes(d[2]==3)))) s+="s";
+        if ((d[0]==6)&&(((d[1]!=0)&&(d[1]==8))||((d[1]==0)&&(d[2]==8)))) s+="x";
+        if ([7,9].includes(d[0])&&(((d[1]!=0)&&[1,3,4,5,6,7].includes(d[1]))||((d[1]==0)&&[2,3,4,5,6,7].includes(d[2])))) s+="n";
+        if ([7,9].includes(d[0])&&(((d[1]!=0)&&((d[1]==2)||(d[1]==8)))||((d[1]==0)&&(d[2]==8)))) s+="m";
+        s+=namefragments[1][d[1]]+namefragments[2][d[2]];
+      }
+      if (mu!==0){
+        if (g<=19){
+          r+=s+namefragments[3][g];
+        }else{
+          r+=s+namefragments[4][g%10]+namefragments[5][Math.floor(g/10)];
+        }
+      }
+    }
+    var w=r.charAt(r.length-1);
+    if (["a","i","o"].includes(w)) r=r.substr(0,r.length-1);
+    r+="illion";
+    return Math.floor(Number(i.div(new Decimal("1e+"+e)))*1000)/1000+" "+r;
+  }
+});