-
Notifications
You must be signed in to change notification settings - Fork 0
Expand file tree
/
Copy path155_min_stack.cpp
More file actions
77 lines (63 loc) · 1.75 KB
/
155_min_stack.cpp
File metadata and controls
77 lines (63 loc) · 1.75 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
/*
LeetCode 155 - Min Stack
Difficulty: Medium
Problem:
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
Implement the MinStack class:
- MinStack() initializes the stack object.
- void push(int val) pushes the element val onto the stack.
- void pop() removes the element on the top of the stack.
- int top() gets the top element of the stack.
- int getMin() retrieves the minimum element in the stack.
Example 1:
Input: ["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
Output: [null,null,null,null,-3,null,0,-2]
Constraints:
-2^31 <= val <= 2^31 - 1
Methods pop, top and getMin operations will always be called on non-empty stacks.
At most 3 * 10^4 calls will be made to push, pop, top, and getMin.
Time Complexity: O(1) for all operations
Space Complexity: O(n)
*/
#include <iostream>
#include <stack>
#include <algorithm>
using namespace std;
class MinStack {
private:
stack<int> st;
stack<int> min_st; // Tracks the current minimum at each level
public:
MinStack() {
}
void push(int val) {
st.push(val);
int min_val = val;
if (!min_st.empty()) {
min_val = min(val, min_st.top());
}
min_st.push(min_val);
}
void pop() {
st.pop();
min_st.pop();
}
int top() {
return st.top();
}
int getMin() {
return min_st.top();
}
};
int main() {
MinStack minStack;
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
cout << minStack.getMin() << endl; // -3
minStack.pop();
cout << minStack.top() << endl; // 0
cout << minStack.getMin() << endl; // -2
return 0;
}