@@ -40,7 +40,8 @@ u = ModelingToolkit.varmap_to_vars(
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Dict ([S (k - 1 ) => 1 , I (k - 1 ) => 2 , R (k - 1 ) => 3 ]), unknowns (syss))
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p = MTKParameters (syss, [c, nsteps, δt, β, γ] .=> collect (1 : 5 ))
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df. f (du, u, p, 0 )
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- reorderer = getu (syss, [S, I, R])
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+ @test_broken getu (syss, [S, I, R])
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+ reorderer = getu (syss, [S (k - 1 ), I (k - 1 ), R (k - 1 )])
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@test reorderer (du) ≈ [0.01831563888873422 , 0.9816849729159067 , 4.999999388195359 ]
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# oop
@@ -57,7 +58,8 @@ prob_map = DiscreteProblem(syss, [u0; p], tspan)
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# Solution
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using OrdinaryDiffEq
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sol_map = solve (prob_map, FunctionMap ());
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- @test sol_map[S] isa Vector
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+ @test_broken sol_map[S] isa Vector
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+ @test sol_map[S (k - 1 )] isa Vector
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# Using defaults constructor
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@parameters c= 10.0 nsteps= 400 δt= 0.1 β= 0.05 γ= 0.25
@@ -73,18 +75,19 @@ eqs2 = [S ~ S(k - 1) - infection2,
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R2 ~ R]
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@mtkcompile sys = System (
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- eqs2, t, [S, I, R, R2], [c, nsteps, δt, β, γ]; controls = [β, γ], tspan )
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+ eqs2, t, [S, I, R, R2], [c, nsteps, δt, β, γ])
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@test ModelingToolkit. defaults (sys) != Dict ()
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- prob_map2 = DiscreteProblem (sys)
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+ @test_broken DiscreteProblem (sys, [], tspan)
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+ prob_map2 = DiscreteProblem (sys, [S (k - 1 ) => S, I (k - 1 ) => I, R (k - 1 ) => R], tspan)
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sol_map2 = solve (prob_map2, FunctionMap ());
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@test sol_map. u ≈ sol_map2. u
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for p in parameters (sys)
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@test sol_map. prob. ps[p] ≈ sol_map2. prob. ps[p]
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end
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- @test_throws Any sol_map2[R2]
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- @test sol_map2[R2 (k + 1 )][begin : (end - 1 )] == sol_map2[R][(begin + 1 ): end ]
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+ @test sol_map2[R2][ begin : ( end - 1 )] == sol_map2[ R (k - 1 )][( begin + 1 ) : end ]
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+ @test_broken sol_map2[R2 (k + 1 )][begin : (end - 1 )] == sol_map2[R][(begin + 1 ): end ]
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# Direct Implementation
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function sir_map! (u_diff, u, p, t)
@@ -100,12 +103,14 @@ function sir_map!(u_diff, u, p, t)
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end
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nothing
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end ;
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- u0 = prob_map2[[S, I, R]];
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+ @test_broken prob_map2[[S, I, R]]
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+ u0 = prob_map2[[S (k - 1 ), I (k - 1 ), R (k - 1 )]];
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p = [0.05 , 10.0 , 0.25 , 0.1 ];
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prob_map = DiscreteProblem (sir_map!, u0, tspan, p);
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sol_map2 = solve (prob_map, FunctionMap ());
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- @test reduce (hcat, sol_map[[S, I, R]]) ≈ Array (sol_map2)
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+ @test_broken reduce (hcat, sol_map[[S, I, R]]) ≈ Array (sol_map2)
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+ @test reduce (hcat, sol_map[[S (k - 1 ), I (k - 1 ), R (k - 1 )]]) ≈ Array (sol_map2)
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# Delayed difference equation
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# @variables x(..) y(..) z(t)
@@ -245,79 +250,78 @@ end
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@test_nowarn @mtkcompile sys = System (; buffer = ones (10 ))
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- # Ensure discrete systems with algebraic equations throw
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- @variables x (t) y (t)
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- k = ShiftIndex (t)
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- @named sys = System ([x ~ x^ 2 + y^ 2 , y ~ x (k - 1 ) + y (k - 1 )], t)
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-
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@testset " Passing `nothing` to `u0`" begin
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- @variables x (t) = 1
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- k = ShiftIndex ()
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- @mtkcompile sys = System ([x (k) ~ x (k - 1 ) + 1 ], t)
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- prob = @test_nowarn DiscreteProblem (sys, nothing , (0.0 , 1.0 ))
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- @test_nowarn solve (prob, FunctionMap ())
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+ @test_broken begin
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+ @variables x (t) = 1
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+ k = ShiftIndex ()
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+ @mtkcompile sys = System ([x (k) ~ x (k - 1 ) + 1 ], t)
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+ prob = @test_nowarn DiscreteProblem (sys, nothing , (0.0 , 1.0 ))
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+ @test_nowarn solve (prob, FunctionMap ())
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+ end
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end
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@testset " Initialization" begin
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- # test that default values apply to the entire history
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- @variables x (t) = 1.0
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- @mtkcompile de = System ([x ~ x (k - 1 ) + x (k - 2 )], t)
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- prob = DiscreteProblem (de, [], (0 , 10 ))
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- @test prob[x] == 2.0
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- @test prob[x (k - 1 )] == 1.0
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-
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- # must provide initial conditions for history
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- @test_throws ErrorException DiscreteProblem (de, [x => 2.0 ], (0 , 10 ))
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- @test_throws ErrorException DiscreteProblem (de, [x (k + 1 ) => 2.0 ], (0 , 10 ))
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-
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- # initial values only affect _that timestep_, not the entire history
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- prob = DiscreteProblem (de, [x (k - 1 ) => 2.0 ], (0 , 10 ))
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- @test prob[x] == 3.0
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- @test prob[x (k - 1 )] == 2.0
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- @variables xₜ₋₁ (t)
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- @test prob[xₜ₋₁] == 2.0
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-
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- # Test initial assignment with lowered variable
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- prob = DiscreteProblem (de, [xₜ₋₁ (k - 1 ) => 4.0 ], (0 , 10 ))
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- @test prob[x (k - 1 )] == prob[xₜ₋₁] == 1.0
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- @test prob[x] == 5.0
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-
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- # Test missing initial throws error
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- @variables x (t)
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- @mtkcompile de = System ([x ~ x (k - 1 ) + x (k - 2 ) * x (k - 3 )], t)
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- @test_throws ErrorException prob= DiscreteProblem (de, [x (k - 3 ) => 2.0 ], (0 , 10 ))
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- @test_throws ErrorException prob= DiscreteProblem (
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- de, [x (k - 3 ) => 2.0 , x (k - 1 ) => 3.0 ], (0 , 10 ))
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-
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- # Test non-assigned initials are given default value
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- @variables x (t) = 2.0
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- @mtkcompile de = System ([x ~ x (k - 1 ) + x (k - 2 ) * x (k - 3 )], t)
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- prob = DiscreteProblem (de, [x (k - 3 ) => 12.0 ], (0 , 10 ))
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- @test prob[x] == 26.0
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- @test prob[x (k - 1 )] == 2.0
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- @test prob[x (k - 2 )] == 2.0
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-
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- # Elaborate test
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- @variables xₜ₋₂ (t) zₜ₋₁ (t) z (t)
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- eqs = [x ~ x (k - 1 ) + z (k - 2 ),
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- z ~ x (k - 2 ) * x (k - 3 ) - z (k - 1 )^ 2 ]
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- @mtkcompile de = System (eqs, t)
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- u0 = [x (k - 1 ) => 3 ,
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- xₜ₋₂ (k - 1 ) => 4 ,
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- x (k - 2 ) => 1 ,
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- z (k - 1 ) => 5 ,
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- zₜ₋₁ (k - 1 ) => 12 ]
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- prob = DiscreteProblem (de, u0, (0 , 10 ))
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- @test prob[x] == 15
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- @test prob[z] == - 21
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-
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- import ModelingToolkit: shift2term
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- # unknowns(de) = xₜ₋₁, x, zₜ₋₁, xₜ₋₂, z
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- vars = sort (ModelingToolkit. value .(unknowns (de)); by = string)
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- @test isequal (shift2term (Shift (t, 1 )(vars[2 ])), vars[1 ])
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- @test isequal (shift2term (Shift (t, 1 )(vars[3 ])), vars[2 ])
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- @test isequal (shift2term (Shift (t, - 1 )(vars[4 ])), vars[5 ])
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- @test isequal (shift2term (Shift (t, - 2 )(vars[1 ])), vars[3 ])
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+ @test_broken begin
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+ # test that default values apply to the entire history
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+ @variables x (t) = 1.0
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+ @mtkcompile de = System ([x ~ x (k - 1 ) + x (k - 2 )], t)
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+ prob = DiscreteProblem (de, [], (0 , 10 ))
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+ @test prob[x] == 2.0
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+ @test prob[x (k - 1 )] == 1.0
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+
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+ # must provide initial conditions for history
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+ @test_throws ErrorException DiscreteProblem (de, [x => 2.0 ], (0 , 10 ))
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+ @test_throws ErrorException DiscreteProblem (de, [x (k + 1 ) => 2.0 ], (0 , 10 ))
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+
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+ # initial values only affect _that timestep_, not the entire history
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+ prob = DiscreteProblem (de, [x (k - 1 ) => 2.0 ], (0 , 10 ))
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+ @test prob[x] == 3.0
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+ @test prob[x (k - 1 )] == 2.0
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+ @variables xₜ₋₁ (t)
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+ @test prob[xₜ₋₁] == 2.0
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+
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+ # Test initial assignment with lowered variable
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+ prob = DiscreteProblem (de, [xₜ₋₁ (k - 1 ) => 4.0 ], (0 , 10 ))
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+ @test prob[x (k - 1 )] == prob[xₜ₋₁] == 1.0
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+ @test prob[x] == 5.0
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+
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+ # Test missing initial throws error
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+ @variables x (t)
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+ @mtkcompile de = System ([x ~ x (k - 1 ) + x (k - 2 ) * x (k - 3 )], t)
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+ @test_throws ErrorException prob= DiscreteProblem (de, [x (k - 3 ) => 2.0 ], (0 , 10 ))
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+ @test_throws ErrorException prob= DiscreteProblem (
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+ de, [x (k - 3 ) => 2.0 , x (k - 1 ) => 3.0 ], (0 , 10 ))
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+
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+ # Test non-assigned initials are given default value
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+ @variables x (t) = 2.0
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+ @mtkcompile de = System ([x ~ x (k - 1 ) + x (k - 2 ) * x (k - 3 )], t)
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+ prob = DiscreteProblem (de, [x (k - 3 ) => 12.0 ], (0 , 10 ))
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+ @test prob[x] == 26.0
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+ @test prob[x (k - 1 )] == 2.0
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+ @test prob[x (k - 2 )] == 2.0
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+
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+ # Elaborate test
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+ @variables xₜ₋₂ (t) zₜ₋₁ (t) z (t)
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+ eqs = [x ~ x (k - 1 ) + z (k - 2 ),
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+ z ~ x (k - 2 ) * x (k - 3 ) - z (k - 1 )^ 2 ]
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+ @mtkcompile de = System (eqs, t)
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+ u0 = [x (k - 1 ) => 3 ,
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+ xₜ₋₂ (k - 1 ) => 4 ,
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+ x (k - 2 ) => 1 ,
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+ z (k - 1 ) => 5 ,
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+ zₜ₋₁ (k - 1 ) => 12 ]
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+ prob = DiscreteProblem (de, u0, (0 , 10 ))
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+ @test prob[x] == 15
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+ @test prob[z] == - 21
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+
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+ import ModelingToolkit: shift2term
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+ # unknowns(de) = xₜ₋₁, x, zₜ₋₁, xₜ₋₂, z
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+ vars = sort (ModelingToolkit. value .(unknowns (de)); by = string)
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+ @test isequal (shift2term (Shift (t, 1 )(vars[2 ])), vars[1 ])
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+ @test isequal (shift2term (Shift (t, 1 )(vars[3 ])), vars[2 ])
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+ @test isequal (shift2term (Shift (t, - 1 )(vars[4 ])), vars[5 ])
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+ @test isequal (shift2term (Shift (t, - 2 )(vars[1 ])), vars[3 ])
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+ end
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end
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@testset " Shifted array variables" begin
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(0 , 4 ))
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@test all (isone, prob. u0)
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sol = solve (prob, FunctionMap ())
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- @test sol[[x... , y... ], end ] == 8 ones (4 )
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+ @test_broken sol[[x... , y... ], end ]
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+ @test sol[[x (k - 1 )... , y (k - 1 )... ], end ] == 8 ones (4 )
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end
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