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When you connect a dynamic input pin with the same key, both pins will always be treated identically.
The example above: output is connected to #key1, but the #key1 on the other non-connected block also loses its input field indicating it's also connected
The text was updated successfully, but these errors were encountered:
When you connect a dynamic input pin with the same key, both pins will always be treated identically.
The example above: output is connected to #key1, but the #key1 on the other non-connected block also loses its input field indicating it's also connected
The text was updated successfully, but these errors were encountered: