pythonScript/callAndPrototypeTestNew.html at master · SmoothLatte/pythonScript · GitHub

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<html>
<head>
	<meta charset="utf-8">
</head>
<body>
<script type="text/javascript">
	//person类
	function person(name, age) {
		this.name = name;
		this.age = age;
	}

	//student类，继承自person(call)
	function student(name, age, no) {
		person.call(this, name, age);
		this.no = no;
	}

	//programer类，继承自person(prototype)
	function programer(name, age, sex) {
		this.sex = sex;
	}
	programer.prototype = new person();

	//man类，继承自person(prototype)
	function man(name, age, height) {
		person.call(this, name, age);
		this.height = height;
		this
	}
	man.prototype.say = function() {
		alert(this.name);
	};


	//创建person实例
	var p = new person("captain", 21);
	//创建student实例
	var s = new student("captain", 21, "06281097");
	//创建programer实例
	var g = new programer("captain", 21, "男");
	//创建man实例
	var m = new man("captain", 21, 176);

	//判断类型(typeof返回全是object，所以用instanceof)
	alert(s instanceof person);//false 使用call并不是完全的继承
	alert(s instanceof student);//true
	alert(g instanceof person);//true
	alert(g instanceof programer);//true
	alert(m instanceof person);//false
	//只有使用prototype添加父类的构造函数,才能在意义上完全继承person
	alert(m instanceof man);//true
<script>
</body>
</html>