Restructured entire project to be a quarto website to put on github

pages

Author: Soybean44

.github/workflows/publish.yml

@@ -0,0 +1,26 @@
+on:
+  workflow_dispatch:
+  push:
+    branches: main
+
+name: Quarto Publish
+
+jobs:
+  build-deploy:
+    runs-on: ubuntu-latest
+    permissions:
+      contents: write
+    steps:
+      - name: Check out repository
+        uses: actions/checkout@v4
+
+      - name: Set up Quarto
+        uses: quarto-dev/quarto-actions/setup@v2
+
+      - name: Render and Publish
+        uses: quarto-dev/quarto-actions/publish@v2
+        with:
+          target: gh-pages
+          render: false
+        env:
+          GITHUB_TOKEN: ${{ secrets.GITHUB_TOKEN }}

.gitignore

@@ -1 +1,2 @@
-**.quarto/
+/.quarto/
+/_site/

_freeze/experiments/schrodingers/index/execute-results/html.json

@@ -0,0 +1,12 @@
+{
+  "hash": "08c5215eee86187430c771eb0be34bc2",
+  "result": {
+    "engine": "jupyter",
+    "markdown": "---\ntitle: Poisson's Equation (Voltage)\nimage: voltage.png\n---\n\nImport required libraries\n\n::: {#23089e97 .cell execution_count=2}\n``` {.python .cell-code}\nimport matplotlib.pyplot as plt\nfrom matplotlib.animation import FuncAnimation\nimport numpy as np\nfrom IPython.display import HTML\n```\n:::\n\n\nSet up the data required\n\n::: {#1d3c9a20 .cell execution_count=3}\n``` {.python .cell-code}\nsize = 50\nvoltages = np.zeros((size, size))\nV0 = 50\ncond = -0.5\nvoltages[10, 10] = V0\n```\n:::\n\n\nThe partial differential equation we are solving is \n$$\n  \\nabla V = -\\frac{1}{\\epsilon_0}\\rho\n$$\n\nthe right hand side is `cond`. Then we can solve this with the boundaries of a 50x50 having a voltage of 0.\nTo solve this we can use the following formula for $u_{i,j}$\n$$\nu_{i,j} = \\frac{1}{4}(u_{i,j+1}+u_{i+1,j}+u_{i,j-1}+u_{i-1,j}-cond)\n$$\n\n::: {#d183702c .cell execution_count=4}\n``` {.python .cell-code}\nfor _ in range(500):\n    for i in range(size):\n        for j in range(size):\n            u1 = voltages[i, j + 1] if j + 1 < size else 0\n            u2 = voltages[i, j - 1] if j - 1 > -1 else 0\n            u3 = voltages[i + 1, j] if i + 1 < size else 0\n            u4 = voltages[i - 1, j] if i - 1 > -1 else 0\n            voltages[i, j] = (u1 + u2 + u3 + u4 - cond) / 4\n```\n:::\n\n\nThen we get the  gradient of this to find the electric field\n\n::: {#56e4bf15 .cell execution_count=5}\n``` {.python .cell-code}\npos = np.array(range(size))\n\ndy, dx = np.gradient(-voltages, pos, pos)\n```\n:::\n\n\nThen we graph it \n\n::: {#1a828a65 .cell execution_count=6}\n``` {.python .cell-code}\nskip = 5  # Number of points to skip\nplt.figure()\nplt.imshow(\n    np.abs(voltages),\n    extent=(0, size, 0, size),\n    origin=\"lower\",\n    cmap=\"viridis\",\n)\nplt.colorbar(label=\"Voltage\")\nplt.quiver(\n    pos[::skip],\n    pos[::skip],\n    dx[::skip, ::skip],\n    dy[::skip, ::skip],\n    color=\"r\",\n    headlength=3,\n)\nplt.title(\"Scalar Field using contour\")\nplt.xlabel(\"X-axis\")\nplt.ylabel(\"Y-axis\")\n\nplt.show()\n```\n\n::: {.cell-output .cell-output-display}\n![](index_files/figure-html/cell-6-output-1.png){}\n:::\n:::\n\n\n",
+    "supporting": [
+      "index_files/figure-html"
+    ],
+    "filters": [],
+    "includes": {}
+  }
+}