@@ -305,19 +305,19 @@ \subsection{Move to a better place (Ch.\ 11 or 2)}
305305Let $ A$ and $ B$ be pointed types and
306306let $ f: A\ptdto B$ be a pointed map.
307307Then we have an identification of $ O(f)\circ \ev _A$
308- and $ \ev _B \circ {\loops (f)}$ , as represented by \cref {fig:Omega-O }.
309- Consequently, we have that $ e\defeq (\inv { \ ev _B} \circ {{\blank }\circ\ev _A})$
310- is a pointed equivalence of type
308+ and $ { \ev _B} \circ {\loops (f)}$ , as represented by \cref {fig:Omega-O }.
309+ Consequently, we have that $ e\defeq (\ev _B\circ {{\blank }\circ\inv { \ ev _A} })$
310+ is an equivalence of type
311311$ (\loops A\ptdto\loops B)\equivto (\Sc A\ptdto\Sc B)$
312312with $ O \eqto (e\circ \loops )$ .
313313\end {construction }
314314\begin {implementation }{con:Omega-O}
315315Elaborating the situation in \cref {fig:Omega-O }, we have to
316- identify (1) and (2) for all $ (p,p_\pt )$ by a map $ e $ and
316+ identify (1) and (2) for all $ (p,p_\pt )$ by a map $ i $ and
317317give an identification to fill the following diagram:
318318
319319\begin {tikzcd }[ampersand replacement=\& ]
320- \& \& \inv {f_\pt }\cdot f(\cst {\pt _A}(\Sloop )\cdot \refl {})\cdot f_\pt \ar [dddd,eqr,"{e (\cst {\pt _A},\refl {\pt _A})}"]
320+ \& \& \inv {f_\pt }\cdot f(\cst {\pt _A}(\Sloop )\cdot \refl {})\cdot f_\pt \ar [dddd,eqr,"{i (\cst {\pt _A},\refl {\pt _A})}"]
321321\\
322322 \& \loops (f)(\refl {\pt _A})
323323 \ar [ru,eqr,"{\loops (f)((\ev _A)_\pt )}"]
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