LeetCode: https://leetcode.com/problems/best-time-to-buy-and-sell-stock/ Difficulty: Medium
Solve this arrays problem efficiently.
function solve(nums) {
let result = [];
// Check all possibilities
for (let i = 0; i < nums.length; i++) {
for (let j = i + 1; j < nums.length; j++) {
// Process pairs
if (/* condition */) {
result.push([i, j]);
}
}
}
return result;
}⏱️ Time: O(n²) or O(n³)
💾 Space: O(n)
function solve(nums) {
const map = new Map();
const result = [];
for (let i = 0; i < nums.length; i++) {
// Use hash map for O(1) lookup
const complement = target - nums[i];
if (map.has(complement)) {
result.push([map.get(complement), i]);
}
map.set(nums[i], i);
}
return result;
}⏱️ Time: O(n) or O(n log n)
💾 Space: O(n) or O(1)
Array: [a, b, c, d, e]
Index: 0 1 2 3 4
Two Pointers:
L R
↓ ↓
[a, b, c, d, e]
Process: Move pointers based on condition
L → ← R
Visit LeetCode for full problem description.