LeetCode: https://leetcode.com/problems/binary-search/ Difficulty: Medium
Solve this binary-search problem efficiently.
function solve(nums) {
let result = [];
// Check all possibilities
for (let i = 0; i < nums.length; i++) {
for (let j = i + 1; j < nums.length; j++) {
// Process pairs
if (/* condition */) {
result.push([i, j]);
}
}
}
return result;
}⏱️ Time: O(n²) or O(n³)
💾 Space: O(n)
function solve(nums) {
const map = new Map();
const result = [];
for (let i = 0; i < nums.length; i++) {
// Use hash map for O(1) lookup
const complement = target - nums[i];
if (map.has(complement)) {
result.push([map.get(complement), i]);
}
map.set(nums[i], i);
}
return result;
}⏱️ Time: O(n) or O(n log n)
💾 Space: O(n) or O(1)
Array: [1, 3, 5, 7, 9, 11]
L M R
Target: 7
Step 1: M=5, 7>5, move L
Step 2: [5, 7, 9, 11]
L M R
Found at M!
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