prepared URL API

[x0zzz]

Is there a way to get prepared URL, which will be used in a query? Something like:

req = ClientSession().Request(method='GET', url='http://path.org', data={'a':1, 'b':2})
url = req.prepared_url() -> 'http://path.org?a=1&b=2'
req.headers.update({'auth': auth_fun(url)})

I need this for authentication purposes.
Till now I used requests.Request.prepare().path_url for the URL and yet sent aiohttp request, but I just found out that sometimes the argument ordering in the output URL will differ between the libraries. Nasty bug.

My first reflex was to try with ClientRequest but it requries YARL's URL object (I think?), which is doable I guess, but maybe there's something short and sweet already available.

Can you please help me out?

[asvetlov]

We have no such functionality yet but not maybe we need to invite something.

[kxepal]

Isn't yarl about this? IIRC, it's possible to pass yarl.URL instance as url to request object.

[asvetlov]

Yes, sure.
requests.PreparedRequest contains headers also.
Not sure if we need it though.