showfunc

#!/usr/bin/env python2

import sys,os,re,subprocess

def line_is_function_decl(line, func_name):
    #match bash explicit function declaration
    #function func_name {}
    x = re.compile(r'\s*function\s+%s[\s{(]' % func_name)
    m = x.match(line)
    if m:
        return True
    #match bash implicit function declaration
    #func_name() {}
    x = re.compile(r'\s*%s\s*\(\)' % func_name)
    m = x.match(line)
    if m:
        return True
    return False


if len(sys.argv) < 2:
    print "Usage: %s _function_name_" % os.path.basename(sys.argv[0])
    print "       shows code for a function from functions.bash"
else:
    #TODO: call which on arg, only search functions if not found
    #TODO: figure out way to access calling shell's function environment from python
    with open(os.path.join(os.environ['HOME'],'bin', 'functions.bash'), 'r') as funfile:
        #a couple of flags -- primitive state machine
        printing = False
        isfirstline = False
        for line in funfile:
            line = line[:-1]
            if line_is_function_decl(line, sys.argv[1]):
                isfirstline = True
                printing = True
            else:
                isfirstline = False
            if printing:
                print line
                #cheating here. I think you can have nested {}, and of
                #course the } doesn't have to start the line, that's just
                #my coding convention
            if line.startswith('}'):
                printing = False
            #special case: func definition on one line
            if isfirstline and line.endswith('}'):
                printing = False