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FindLargestValueInEachTreeRow.java
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import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Queue;
/**
* LeetCode
* 515. Find Largest Value in Each Tree Row
* https://leetcode.com/problems/find-largest-value-in-each-tree-row/
* #Medium #Tree
*/
public class FindLargestValueInEachTreeRow {
@SuppressWarnings("unused")
private static class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode() {
}
TreeNode(int val) {
this.val = val;
}
TreeNode(int val, TreeNode left, TreeNode right) {
this.val = val;
this.left = left;
this.right = right;
}
}
public static void main(String[] args) {
FindLargestValueInEachTreeRow sol = new FindLargestValueInEachTreeRow();
System.out.println(sol.largestValues(buildBstFromLevelOrder(new Integer[]{1, 3, 2, 5, 3, null, 9}))); // [1,3,9]
System.out.println(sol.largestValues(buildBstFromLevelOrder(new Integer[]{1, 2, 3}))); // [1,3]
System.out.println(sol.largestValues(buildBstFromLevelOrder(new Integer[]{1}))); // [1]
System.out.println(sol.largestValues(buildBstFromLevelOrder(new Integer[]{1, null, 2}))); // [1,2]
System.out.println(sol.largestValues(buildBstFromLevelOrder(new Integer[]{}))); // []
System.out.println(sol.largestValues(buildBstFromLevelOrder(new Integer[]{0, -1}))); // [0,-1]
}
public List<Integer> largestValues(TreeNode root) {
if (root == null) return Collections.emptyList();
Map<Integer, Integer> maxPerRow = new HashMap<>();
largestValues0(root, 0, maxPerRow);
List<Integer> res = new ArrayList<>();
int i = 0;
while (maxPerRow.containsKey(i)) {
res.add(maxPerRow.get(i));
i++;
}
return res;
}
private void largestValues0(TreeNode node, int level, Map<Integer, Integer> maxPerRow) {
if (node == null) return;
maxPerRow.put(level, Math.max(node.val, maxPerRow.getOrDefault(level, Integer.MIN_VALUE)));
largestValues0(node.left, level + 1, maxPerRow);
largestValues0(node.right, level + 1, maxPerRow);
}
private static TreeNode buildBstFromLevelOrder(Integer[] order) {
if (order == null || order.length == 0) return null;
TreeNode head = null;
Queue<TreeNode> nodes = new ArrayDeque<>();
TreeNode node;
boolean left = true;
for (Integer val : order) {
node = val == null ? null : new TreeNode(val);
if (head == null) {
head = node;
if (head == null) return null;
}
if (!nodes.isEmpty()) {
if (left) nodes.peek().left = node;
else nodes.poll().right = node;
left = !left;
}
if (node != null) {
nodes.add(node);
}
}
return head;
}
}