@LLFourn mentioned in a private discussion:
... in theory the combined will be looser than each individual one in the sense that it will take more iterations to find the optimal solution for the combined one I think. (A,B) has to find an optimal solution for A but this will not necessarily be optimal for (A,B) so it has to keep looking.
I responded with:
Would you agree that combining another metric with Changeless is only useful if it tightens the bounds? Otherwise, we might as will do Iterator::filter on the BnbIter.
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