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There is a bug that the zipfile support was deleted from the code base, but you can give the zip name directly instead mf4 = MDF('XXX_BackUp_22-02-21_081529_445.zip') |
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First is first: let me thank you (Daniel and the participants) for the fast and efficient mf4 interpreter implementation. I am impressed on how well it performs when compared with the ones provided by other popular SWs.
I am currently benchmarking access times for several options, and I found a problem when trying to access a zipped mf4.
If I run:
mf4 = MDF(zipfile.ZipFile('XXX_BackUp_22-02-21_081529_445.zip'))I get the following error:
I can call with no issues zipfile.ZipFile('XXX_BackUp_22-02-21_081529_445.zip'), or mf4 = MDF('XXX_BackUp_22-02-21_081529_445.mf4).
My asammdf version details:
Name: asammdf
Version: 7.0.7
Summary: ASAM MDF measurement data file parser
Home-page: https://github.com/danielhrisca/asammdf
Author: Daniel Hrisca
Author-email: [email protected]
License: LGPLv3+
Location: /usr/local/lib/python3.7/dist-packages
Requires: canmatrix, lz4, numexpr, numpy, pandas, typing-extensions
Required-by:
Thanks in advance,
Carlos
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