Fix lambda at the end of a word messing up python spacing

Author: davidshepherd7

electric-operator.el

@@ -863,7 +863,7 @@ Also handles C++ lambda capture by reference."
 (defun electric-operator-python-mode-in-lambda-args? ()
   "Are we inside the arguments statement of a lambda?"
   ;; \\(\\s-\\|^\\) instead of just \\b because otherwise foo_lambda matches
-  (electric-operator-looking-back-locally "\\(\\s-\\|^\\)lambda[^:]*"))
+  (electric-operator-looking-back-locally "\\(\\s-\\|^\\)lambda\\s-[^:]*"))
 
 (defun electric-operator-python-mode-: ()
   "Handle python dict assignment"

features/python-mode.feature

@@ -164,10 +164,18 @@ Feature: Python mode basics
     When I type "foolambdabar=1"
     Then I should see "foolambdabar = 1"
 
+  Scenario: Lambda at the start of another word doesn't affect spacing
+    When I type "lambdabar=1"
+    Then I should see "lambdabar = 1"
+
   Scenario: Lambda inside another word with _ doesn't affect spacing
     When I type "foo_lambdabar=1"
     Then I should see "foo_lambdabar = 1"
 
+  Scenario: Zero argument lambda
+    When I type "lambda: x, y=1"
+    Then I should see "lambda: x, y = 1"
+
   # Slice operator
   Scenario: Don't space : inside slices
     When I type "a[1:2]"