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executable file
·77 lines (74 loc) · 2.3 KB
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class Solution1658 {
public int minOperations(int[] nums, int x) {
int[] presum = new int[nums.length + 1];
for (int i = 0; i < nums.length; i++) {
presum[i + 1] = presum[i] + nums[i];
}
int left = 1, right = nums.length;
// 根据最小值确定右边界
while (left < right - 1) {
int mid = (left + right) / 2;
int temp = minValue(presum, mid);
if (temp > x) {
right = mid;
}
else {
left = mid;
}
}
int maxlen = right;
left = 1;
right = nums.length;
// 根据最大值确定左边界
while (left < right - 1) {
int mid = (left + right) / 2;
int temp = maxValue(presum, mid);
if (temp < x) {
left = mid;
}
else {
right = mid;
}
}
int minlen = left;
for (int i = minlen; i <= maxlen; i++) {
if (isValue(presum, x, i) == 0) return i;
}
return -1;
}
public int minValue(int[] presum, int k) {
/**
* 记录 k 次操作数能取到的最小值
*/
int maxsum = Integer.MIN_VALUE;
int len = presum.length - 1 - k;
for (int i = len; i < presum.length; i++) {
int temp = presum[i] - presum[i - len];
maxsum = Math.max(maxsum, temp);
}
return presum[presum.length - 1] - maxsum;
}
public int maxValue(int[] presum, int k) {
/**
* 记录 k 次操作数能取到的最大值
*/
int minsum = Integer.MAX_VALUE;
int len = presum.length - 1 - k;
for (int i = len; i < presum.length; i++) {
int temp = presum[i] - presum[i - len];
minsum = Math.min(minsum, temp);
}
return presum[presum.length - 1] - minsum;
}
public int isValue(int[] presum, int x, int k) {
/**
* 记录 k 次操作数是否能取到目标值
*/
int len = presum.length - 1 - k;
for (int i = len; i < presum.length; i++) {
int temp = presum[i] - presum[i - len];
if (temp == presum[presum.length - 1] - x) return 0;
}
return -1;
}
}