refactor: Use [...foo, bar] instead of foo.concat(bar)

Author: eemeli

src/doc/Document.ts

@@ -205,7 +205,7 @@ export class Document<
       const keyToStr = (v: unknown) =>
         typeof v === 'number' || v instanceof String || v instanceof Number
       const asStr = replacer.filter(keyToStr).map(String)
-      if (asStr.length > 0) replacer = replacer.concat(asStr)
+      if (asStr.length > 0) replacer = [...replacer, ...asStr]
       nc = new NodeCreator(this, options, replacer)
     } else {
       options ??= replacer ?? undefined

src/parse/parser.ts

@@ -641,7 +641,7 @@ export class Parser {
               })
             } else if (start.length > 0) {
               // Not actually at next item
-              it.sep = it.sep.concat(start, this.sourceToken)
+              it.sep = [...it.sep, ...start, this.sourceToken]
             } else {
               it.sep.push(this.sourceToken)
             }

src/schema/tags.ts

@@ -98,7 +98,7 @@ export function getTags(
   const schemaTags = schemas.get(schemaName)
   if (schemaTags && !customTags) {
     return addMergeTag && !schemaTags.includes(merge)
-      ? schemaTags.concat(merge)
+      ? [...schemaTags, merge]
       : schemaTags.slice()
   }
 
@@ -121,7 +121,7 @@ export function getTags(
   } else if (typeof customTags === 'function') {
     tags = customTags(tags.slice())
   }
-  if (addMergeTag) tags = tags.concat(merge)
+  if (addMergeTag) tags = [...tags, merge]
 
   return tags.reduce<(CollectionTag | ScalarTag)[]>((tags, tag) => {
     const tagObj = typeof tag === 'string' ? tagsByName[tag] : tag