Transform interface wrong?

[rrahn]

Hi I am wondering if the interface of transform is wrong?

According to:

meta/include/meta/meta.hpp

Lines 1522 to 1523 in 9780f35

	template <typename... Args>
	using transform = _t<detail::transform_<list<Args...>>>;

it can only be called with arguments. But where is the fun without a Fun template?
And second, why does transform not expect a list of something like all the other meta algorithms but an unpacked list?
Right now, I am resorting to the detail implementation which seems to be the correct one.

[gabyx]

It accepts a meta::list as the first argument and a Callable as the second.
The documentation is not so user-friendly at this point, yes, maybe one should document it, what the first and second argument shall be.

You need to look closely at the detail namespace:

 namespace detail
 1997         {
 1998             template <typename, typename = void>
 1999             struct transform_
 2000             {
 2001             };
 2002 
 2003             template <typename... Ts, typename Fun>
 2004             struct transform_<list<list<Ts...>, Fun>, void_<invoke<Fun, Ts>...>>
 2005             {
 2006                 using type = list<invoke<Fun, Ts>...>;
 2007             };
 2008 
 2009             template <typename... Ts0, typename... Ts1, typename Fun>
 2010             struct transform_<list<list<Ts0...>, list<Ts1...>, Fun>,
 2011                               void_<invoke<Fun, Ts0, Ts1>...>>
 2012             {
 2013                 using type = list<invoke<Fun, Ts0, Ts1>...>;
 2014             };
 2015         } // namespace detail

[gabyx]

PR #71