Merge pull request #14324 from drjfloyd/master

FDS User Guide: Fix description of methanol_evaporation

Author: drjfloyd

Manuals/FDS_User_Guide/FDS_User_Guide.tex

@@ -3107,7 +3107,7 @@ \subsubsection{Evaporation of a Pure Liquid}
 \be
    \dot{q}''_{\rm total} - \dot{q}''_{\rm c}= \dot{m}'' \, h_{\rm v} \, T_{\rm s}
 \ee
-where $\dot{q}''_{\rm c}$ is the heat being conducted away from the surface. If $\dot{q}''_{\rm c}$ is made zero, which can be done by using \ct{BACKING='INSULATED'} and a high thermal conductivity, then the pool surface temperature,$T_{\rm s}$, will approach the boiling temperature,$T_{\rm b}$. In this example, the methanol evaporates in an oxygen-depleted atmosphere and no burning occurs. The left hand plot in Fig.~\ref{methanol_evaporation_plot} displays the computed evaporation rate, $\dot{m}''$, versus the ideal, $\dot{q}''_{\rm total}/h_{\rm v} T_{\rm b}$. The former approaches the latter as all of the absorbed energy is used to evaporate the liquid. The right hand plot shows the computed liquid surface temperature versus the liquid boiling temperature.
+where $\dot{q}''_{\rm c}$ is the heat being conducted away from the surface. If $\dot{q}''_{\rm c}$ is made zero, which can be done by using \ct{BACKING='INSULATED'} and a high thermal conductivity, then the pool surface temperature,$T_{\rm s}$, will approach the boiling temperature,$T_{\rm b}$. In this example, since there is no gas phase combustion reaction (\ct{REAC}), no burning occurs. The left hand plot in Fig.~\ref{methanol_evaporation_plot} displays the computed evaporation rate, $\dot{m}''$, versus the ideal, $\dot{q}''_{\rm total}/h_{\rm v} T_{\rm b}$. The former approaches the latter as all of the absorbed energy is used to evaporate the liquid. The right hand plot shows the computed liquid surface temperature versus the liquid boiling temperature.
 \begin{figure}[!ht]
 \includegraphics[width=3.2in]{SCRIPT_FIGURES/methanol_evaporation_mdot}
 \includegraphics[width=3.2in]{SCRIPT_FIGURES/methanol_evaporation_temp}