[Question] Rotate property and space #2060
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by
ndonkoHenri
ingdesarr1
asked this question in
Q&A
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QuestionGood afternon. I'm testing the rotate control to use with a Progressbar, to display it vertically. The problem is that when rotating the element, flet detects that it is still occupying the same space horizontally and not vertically. If I reduce the horizontal space, this reduces the element and the display in rotation is affected. How can I make the ProgressBar look vertically but without this problem? I try with a Container, but the problem still. Thanks Code samplefrom time import sleep
import math
import flet as ft
def main(page: ft.Page):
pb = ft.ProgressBar(height=20,width=100,rotate=ft.Rotate(-math.pi/2,alignment=ft.alignment.top_left),value=0)
def cambio(e):
pb.value = e.control.value/100
page.update()
page.add(
ft.Slider(min=0,max=100,divisions=100,label="{value}%",on_change=cambio),
ft.Text("Linear progress indicator", style="headlineSmall"),
ft.Column([ ft.Text("Doing something..."),
ft.Row(
controls=[
# ft.Container(width=10,content=pb,bgcolor="red",rotate=ft.Rotate(-math.pi/2,alignment=ft.alignment.top_left)),
pb,
ft.Container(bgcolor="blue",width=50,height=50)
]
)
]),
)
ft.app(target=main) Error messageNo response ------------------------------------------------------
|
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Answered by
ndonkoHenri
Nov 10, 2023
Replies: 1 comment 1 reply
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This is a bug. |
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1 reply
Answer selected by
ingdesarr1
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This is a bug.
There's an opened issue: #1653