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README.md

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<!-- markdownlint-disable MD041 -->
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[![eevveerryyddaayy release](https://img.shields.io/badge/eevveerryyddaayy-v1.3.0-blue.svg)](https://github.com/ggeerraarrdd/eevveerryyddaayy/)
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[![Solved](https://img.shields.io/badge/solved-188-green.svg)](#index)
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[![Solved](https://img.shields.io/badge/solved-189-green.svg)](#index)
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# SQL Everyday
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| 186 | [Sales Analysis II](https://leetcode.com/problems/sales-analysis-ii/description/) | [Solution](solutions/186_sales_analysis_ii.md) | LeetCode | Easy | `STRING_AGG` vs `GROUP_CONCAT` |
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| 187 | [Sales Analysis III](https://leetcode.com/problems/sales-analysis-iii/description/) | [Solution](solutions/187_sales_analysis_iii.md) | LeetCode | Easy | `HAVING` |
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| 188 | [The Winner University](https://leetcode.com/problems/the-winner-university/description/) | [Solution](solutions/188_the_winner_university.md) | LeetCode | Easy | |
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| 189 | [Unique Orders and Customers Per Month](https://leetcode.com/problems/unique-orders-and-customers-per-month/description/) | [Solution](solutions/189_unique_orders_and_customers_per_month.md) | LeetCode | Easy | |
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<!-- Index End - WARNING: Do not delete or modify this markdown comment. -->
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# SQL Everyday \#189
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## Unique Orders and Customers Per Month
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Site: LeetCode\
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Difficulty per Site: Easy
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## Problem
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Write a solution to find the number of **unique orders** and the number of **unique customers** with invoices **> $20** for each **different month**.
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Return the resulting table in **any order**. [[Full Description](https://leetcode.com/problems/unique-orders-and-customers-per-month/description/)]
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## Submitted Solution
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```sql
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-- Submitted Solution
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SELECT
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TO_CHAR(order_date, 'YYYY-MM') AS month
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,COUNT(DISTINCT order_id) AS order_count
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,COUNT(DISTINCT customer_id) AS customer_count
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FROM Orders
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WHERE invoice > 20
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GROUP BY month
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;
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```
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## Site Solution
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```sql
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-- LeetCode Solution
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-- None
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-- Code Author: Yasin
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-- https://leetcode.com/problems/unique-orders-and-customers-per-month/solutions/960078/mysql-solution
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-- (modified)
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SELECT
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LEFT(order_date, 7) AS month
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,COUNT(DISTINCT order_id) AS order_count
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,COUNT(DISTINCT customer_id) AS customer_count
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FROM Orders
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WHERE invoice > 20
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GROUP BY 1
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;
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```
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## Notes
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TBD
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## NB
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TBD
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Go to [Index](../?tab=readme-ov-file#index)\
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Go to [Overview](../?tab=readme-ov-file)

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