How to use correct Cron() function

[Dregorio1]

Hello I have code like:

// gocron v1.35.2
 
jobs := []string{
"5 * * * ? *", //At 5 minutes past the hour
"30 * * * ? *", //At 30 minutes past the hour
}	
s := gocron.NewScheduler(time.UTC)
for _, j := range jobs {
	_, err := s.CronWithSeconds(j).SingletonMode().Do(doTask)
	if err != nil {
		log.Fatal(err)
	}
}

I use CronWithSeconds() but now I think that I use it wrong. I use this site https://crontab.cronhub.io/ to check the cron. I need parse "5 * * * ? *" -> At 5 minutes past the hour. How can I parse my string to get "proper" time? CronWithSeconds() do not do what I want.

[JohnRoesler]

CronWithSeconds adds an additional field to the left:

So, take your cron tab for every 5 minutes */5 * * * * and prefix with another * -> * */5 * * * *

[Dregorio1]

No, I want to get At 5 minutes past the hour. Maybe I wrongly describe my problem. I thought that 6* has "one" standard. Like in AWS 6* for "5 * * * ? *" return At 5 minutes past the hour and that is what I want to achieve in my code. Also I used https://crontab.cronhub.io/ this website to parse my 6* cron "5 * * * ? *", and I got what I wanted. So I thought CronWithSeconds also works this way. If not, what function should I use to achieve it?

[JohnRoesler]

Do you need seconds at all? If not just use Cron(). If you need to specify the seconds, then it's a standard crontab -> https://crontab.guru/ with the first field (on the left) being seconds

[Dregorio1]

I have 6* and I cannot change that. This https://crontab.cronhub.io/ website parse it correctly (how I want). How can I achieve it in this library?

[Dregorio1]

Do you need seconds at all? If not just use Cron(). If you need to specify the seconds, then it's a standard crontab -> https://crontab.guru/ with the first field (on the left) being seconds

Ok I got it. Thank you :)