dashboard/app: fix create_upload_url bug

tarasmadan · tarasmadan · commit 76e731793e58 · 2024-12-19T17:03:27.000Z
create_upload_url: failed to unmarshal response: json: cannot unmarshal number into Go value of type string
diff --git a/dashboard/app/api.go b/dashboard/app/api.go
@@ -1937,7 +1937,7 @@ func apiCreateUploadURL(c context.Context, payload io.Reader) (interface{}, erro
 	if bucket == "" {
 		return nil, errors.New("not configured")
 	}
-	return fmt.Printf("%s/%s.upload", bucket, uuid.New().String())
+	return fmt.Sprintf("%s/%s.upload", bucket, uuid.New().String()), nil
 }
 
 // apiSaveCoverage reads jsonl data from payload and stores it to coveragedb.

Original file line number	Diff line number	Diff line change
`@@ -1937,7 +1937,7 @@ func apiCreateUploadURL(c context.Context, payload io.Reader) (interface{}, erro`
`1937`	`1937`	`if bucket == "" {`
`1938`	`1938`	`return nil, errors.New("not configured")`
`1939`	`1939`	`}`
`1940`		`- return fmt.Printf("%s/%s.upload", bucket, uuid.New().String())`
	`1940`	`+ return fmt.Sprintf("%s/%s.upload", bucket, uuid.New().String()), nil`
`1941`	`1941`	`}`
`1942`	`1942`
`1943`	`1943`	`// apiSaveCoverage reads jsonl data from payload and stores it to coveragedb.`