Char_Code_Calculation.md

CodeWars Python Solutions

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Char Code Calculation

Given a string, turn each character into its ASCII character code and join them together to create a number - let's call this number total1:

'ABC' --> 'A' = 65, 'B' = 66, 'C' = 67 --> 656667

Then replace any incidence of the number 7 with the number 1, and call this number 'total2':

total1 = 656667
              ^
total2 = 656661
              ^

Then return the difference between the sum of the digits in total1 and total2:

  (6 + 5 + 6 + 6 + 6 + 7)
- (6 + 5 + 6 + 6 + 6 + 1)
-------------------------
                     6

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Given Code

def calc(x):
    pass

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Solution

def calc(x):
    total1 = "".join([str(ord(i)) for i in x])
    total2 = total1.replace("7", "1")
    return sum([int(i) for i in total1]) - sum([int(i) for i in total2])

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