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102.二叉树的层序遍历.js
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74 lines (72 loc) · 1.57 KB
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//给你二叉树的根节点 root ,返回其节点值的 层序遍历 。 (即逐层地,从左到右访问所有节点)。
//
//
//
// 示例 1:
//
//
//输入:root = [3,9,20,null,null,15,7]
//输出:[[3],[9,20],[15,7]]
//
//
// 示例 2:
//
//
//输入:root = [1]
//输出:[[1]]
//
//
// 示例 3:
//
//
//输入:root = []
//输出:[]
//
//
//
//
// 提示:
//
//
// 树中节点数目在范围 [0, 2000] 内
// -1000 <= Node.val <= 1000
//
// Related Topics 树 广度优先搜索 二叉树 👍 1255 👎 0
//leetcode submit region begin(Prohibit modification and deletion)
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var levelOrder = function(root) {
const stack = []
if(root !== null) {
stack.unshift({ level: 0, node: root })
}
const result = new Map()
while (stack.length) {
const { level, node } = stack.pop()
if(result.has(level)) {
const levelResult = result.get(level)
levelResult.push(node.val)
result.set(level, levelResult)
}else {
result.set(level, [node.val])
}
if(node.left) {
stack.unshift({ level: level + 1, node: node.left })
}
if(node.right) {
stack.unshift({ level: level + 1, node: node.right })
}
}
return Array.from(result.values())
};
//leetcode submit region end(Prohibit modification and deletion)