can the sum overflow?

[dilbert-ro]

pretty-algorithms/algorithms/search/binary-search/binary-search.ts

Line 12 in e97dcb7

const mid = Math.floor((end + start) / 2);

[jiayihu]

It's very unlikely that you have numbers so huge to overflow , especially on the client

[utkarshbhatt12]

You can use (start + ((end - start) / 2) to avoid the overflow, in case that happens.