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"""
File: quick_sort.py
Created Time: 2022-11-25
Author: timi (xisunyy@163.com)
"""
class QuickSort:
"""快速排序类"""
def partition(self, nums: list[int], left: int, right: int) -> int:
"""哨兵划分"""
# 以 nums[left] 为基准数
i, j = left, right
while i < j:
while i < j and nums[j] >= nums[left]:
j -= 1 # 从右向左找首个小于基准数的元素
while i < j and nums[i] <= nums[left]:
i += 1 # 从左向右找首个大于基准数的元素
# 元素交换
nums[i], nums[j] = nums[j], nums[i]
# 将基准数交换至两子数组的分界线
nums[i], nums[left] = nums[left], nums[i]
return i # 返回基准数的索引
def quick_sort(self, nums: list[int], left: int, right: int):
"""快速排序"""
# 子数组长度为 1 时终止递归
if left >= right:
return
# 哨兵划分
pivot = self.partition(nums, left, right)
# 递归左子数组、右子数组
self.quick_sort(nums, left, pivot - 1)
self.quick_sort(nums, pivot + 1, right)
class QuickSortMedian:
"""快速排序类(中位基准数优化)"""
def median_three(self, nums: list[int], left: int, mid: int, right: int) -> int:
"""选取三个候选元素的中位数"""
l, m, r = nums[left], nums[mid], nums[right]
if (l <= m <= r) or (r <= m <= l):
return mid # m 在 l 和 r 之间
if (m <= l <= r) or (r <= l <= m):
return left # l 在 m 和 r 之间
return right
def partition(self, nums: list[int], left: int, right: int) -> int:
"""哨兵划分(三数取中值)"""
# 以 nums[left] 为基准数
med = self.median_three(nums, left, (left + right) // 2, right)
# 将中位数交换至数组最左端
nums[left], nums[med] = nums[med], nums[left]
# 以 nums[left] 为基准数
i, j = left, right
while i < j:
while i < j and nums[j] >= nums[left]:
j -= 1 # 从右向左找首个小于基准数的元素
while i < j and nums[i] <= nums[left]:
i += 1 # 从左向右找首个大于基准数的元素
# 元素交换
nums[i], nums[j] = nums[j], nums[i]
# 将基准数交换至两子数组的分界线
nums[i], nums[left] = nums[left], nums[i]
return i # 返回基准数的索引
def quick_sort(self, nums: list[int], left: int, right: int):
"""快速排序"""
# 子数组长度为 1 时终止递归
if left >= right:
return
# 哨兵划分
pivot = self.partition(nums, left, right)
# 递归左子数组、右子数组
self.quick_sort(nums, left, pivot - 1)
self.quick_sort(nums, pivot + 1, right)
class QuickSortTailCall:
"""快速排序类(递归深度优化)"""
def partition(self, nums: list[int], left: int, right: int) -> int:
"""哨兵划分"""
# 以 nums[left] 为基准数
i, j = left, right
while i < j:
while i < j and nums[j] >= nums[left]:
j -= 1 # 从右向左找首个小于基准数的元素
while i < j and nums[i] <= nums[left]:
i += 1 # 从左向右找首个大于基准数的元素
# 元素交换
nums[i], nums[j] = nums[j], nums[i]
# 将基准数交换至两子数组的分界线
nums[i], nums[left] = nums[left], nums[i]
return i # 返回基准数的索引
def quick_sort(self, nums: list[int], left: int, right: int):
"""快速排序(递归深度优化)"""
# 子数组长度为 1 时终止
while left < right:
# 哨兵划分操作
pivot = self.partition(nums, left, right)
# 对两个子数组中较短的那个执行快速排序
if pivot - left < right - pivot:
self.quick_sort(nums, left, pivot - 1) # 递归排序左子数组
left = pivot + 1 # 剩余未排序区间为 [pivot + 1, right]
else:
self.quick_sort(nums, pivot + 1, right) # 递归排序右子数组
right = pivot - 1 # 剩余未排序区间为 [left, pivot - 1]
"""Driver Code"""
if __name__ == "__main__":
# 快速排序
nums = [2, 4, 1, 0, 3, 5]
QuickSort().quick_sort(nums, 0, len(nums) - 1)
print("快速排序完成后 nums =", nums)
# 快速排序(中位基准数优化)
nums1 = [2, 4, 1, 0, 3, 5]
QuickSortMedian().quick_sort(nums1, 0, len(nums1) - 1)
print("快速排序(中位基准数优化)完成后 nums =", nums1)
# 快速排序(递归深度优化)
nums2 = [2, 4, 1, 0, 3, 5]
QuickSortTailCall().quick_sort(nums2, 0, len(nums2) - 1)
print("快速排序(递归深度优化)完成后 nums =", nums2)