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9 lines (9 loc) · 2.06 KB
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id = "abel_ruffini"
title = "Abel–Ruffini theorem"
test = false
module = "LeanEval.Algebra.AbelRuffini"
holes = ["abel_ruffini"]
submitter = "Kim Morrison"
notes = "§57 of Oliver Knill's 'Some Fundamental Theorems in Mathematics' gives the Abel–Ruffini theorem in degree-threshold form: for each n ≥ 1, every complex root of every degree-n rational polynomial lies in solvableByRad ℚ ℂ if and only if n ≤ 4. This packages solvability of all linear, quadratic, cubic, and quartic equations by radicals together with the failure of such a universal statement from degree five onward. Mathlib defines solvableByRad and proves the direction from radical solvability of a root to solvability of the associated Galois group, and the Archive contains a specific nonsolvable quintic, but Mathlib does not currently contain this full degree-boundary theorem. Distinct from the existing solvable_by_radicals_converse problem (the per-polynomial Galois characterization)."
source = "P. Ruffini (1799), N. H. Abel (1824), É. Galois (1832). Listed as §57 in O. Knill, Some Fundamental Theorems in Mathematics (https://people.math.harvard.edu/~knill/graphgeometry/papers/fundamental.pdf); the general-quintic insolvability is #16 on Freek Wiedijk's 'Formalizing 100 Theorems' list (https://www.cs.ru.nl/~freek/100/)."
informal_solution = "For n ≤ 4: every degree-n polynomial over ℚ has a solvable Galois group (subgroups of S₄ are solvable), and by the Galois correspondence for radical extensions (Kummer theory in characteristic zero) a solvable Galois group implies every root lies in solvableByRad — concretely the Cardano formula for cubics and the Ferrari/resolvent reduction for quartics exhibit the roots by radicals. For n ≥ 5: exhibit one degree-n polynomial whose Galois group is not solvable (e.g. a polynomial reducing to X⁵−4X+2 with Galois group S₅, padded by linear factors to degree n), so by the forward direction of Abel–Ruffini some root is not in solvableByRad, refuting the universally-quantified left-hand side. Combining, the iff holds exactly at the boundary n ≤ 4."