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Solution.java
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/// Source : https://leetcode.com/problems/word-ladder/description/
/// Author : liuyubobobo
/// Time : 2018-03-27
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.LinkedList;
/// BFS
/// Time Complexity: O(n*n)
/// Space Complexity: O(n)
public class Solution {
public int ladderLength(String beginWord, String endWord, List<String> wordList) {
int end = wordList.indexOf(endWord);
if(end == -1)
return 0;
if(!wordList.contains(beginWord))
wordList.add(beginWord);
int begin = wordList.indexOf(beginWord);
int n = wordList.size();
boolean[][] g = new boolean[n][n];
for(int i = 0 ; i < n ; i ++)
for(int j = 0 ; j < i ; j ++)
g[j][i] = g[i][j] = similar(wordList.get(i), wordList.get(j));
// bfs
LinkedList<Integer> q = new LinkedList<>();
int[] step = new int[n];
q.addLast(begin);
step[begin] = 1;
while(!q.isEmpty()){
int cur = q.removeFirst();
for(int i = 0 ; i < n ; i ++)
if(step[i] == 0 && g[cur][i]){
if(i == end)
return step[cur] + 1;
step[i] = step[cur] + 1;
q.addLast(i);
}
}
return 0;
}
private boolean similar(String word1, String word2){
if(word1.length() != word2.length() || word1.equals(word2))
throw new IllegalArgumentException();
int diff = 0;
for(int i = 0 ; i < word1.length() ; i ++)
if(word1.charAt(i) != word2.charAt(i)){
diff ++;
if(diff > 1)
return false;
}
return true;
}
public static void main(String[] args) {
ArrayList<String> wordList1 = new ArrayList<String>(
Arrays.asList("hot","dot","dog","lot","log","cog"));
String beginWord1 = "hit";
String endWord1 = "cog";
System.out.println((new Solution()).ladderLength(beginWord1, endWord1, wordList1));
// 5
// ---
ArrayList<String> wordList2 = new ArrayList<String>(
Arrays.asList("a","b","c"));
String beginWord2 = "a";
String endWord2 = "c";
System.out.println((new Solution()).ladderLength(beginWord2, endWord2, wordList2));
// 2
}
}