You are given two strings word1 and word2. You want to construct a string merge in the following way: while either word1 or word2 are non-empty, choose one of the following options:
- If
word1is non-empty, append the first character inword1tomergeand delete it fromword1.<ul> <li>For example, if <code>word1 = "abc" </code>and <code>merge = "dv"</code>, then after choosing this operation, <code>word1 = "bc"</code> and <code>merge = "dva"</code>.</li> </ul> </li> <li>If <code>word2</code> is non-empty, append the <strong>first</strong> character in <code>word2</code> to <code>merge</code> and delete it from <code>word2</code>. <ul> <li>For example, if <code>word2 = "abc" </code>and <code>merge = ""</code>, then after choosing this operation, <code>word2 = "bc"</code> and <code>merge = "a"</code>.</li> </ul> </li>
Return the lexicographically largest merge you can construct.
A string a is lexicographically larger than a string b (of the same length) if in the first position where a and b differ, a has a character strictly larger than the corresponding character in b. For example, "abcd" is lexicographically larger than "abcc" because the first position they differ is at the fourth character, and d is greater than c.
Example 1:
Input: word1 = "cabaa", word2 = "bcaaa" Output: "cbcabaaaaa" Explanation: One way to get the lexicographically largest merge is: - Take from word1: merge = "c", word1 = "abaa", word2 = "bcaaa" - Take from word2: merge = "cb", word1 = "abaa", word2 = "caaa" - Take from word2: merge = "cbc", word1 = "abaa", word2 = "aaa" - Take from word1: merge = "cbca", word1 = "baa", word2 = "aaa" - Take from word1: merge = "cbcab", word1 = "aa", word2 = "aaa" - Append the remaining 5 a's from word1 and word2 at the end of merge.
Example 2:
Input: word1 = "abcabc", word2 = "abdcaba" Output: "abdcabcabcaba"
Constraints:
1 <= word1.length, word2.length <= 3000word1andword2consist only of lowercase English letters.
Related Topics:
Greedy, Suffix Array
// OJ: https://leetcode.com/problems/largest-merge-of-two-strings/
// Author: github.com/lzl124631x
// Time: O(N^2)
// Space: O(N)
class Solution {
public:
string largestMerge(string word1, string word2) {
priority_queue<string> q;
q.push(word1);
q.push(word2);
string ans;
while (q.size()) {
auto s = q.top();
q.pop();
ans += s[0];
if (s.size() > 1) q.push(s.substr(1));
}
return ans;
}
};find better solution