Stream Problem

[zdh3303]

hi，how can I create Stream in the server size once the client connect to the server，and the server send data to the client(the client only receives the data send by the server). I call StreamOpen method in the server side, however, the client does not receive any message about the stream

[AvatarGanymede]

I meet the same problem. The server calls StreamStart(), but on the client side, the QUIC_CONNECTION_EVENT_PEER_STREAM_STARTED event is not triggered at all.

[AvatarGanymede]

I SOLVE IT! The stream must send a datagram to the peer, then the peer will be notified.

[AvatarGanymede]

Thanks for your reply!

[nibanks]

Oh, you were just opening/starting the stream, and not sending anything? If you want that to indicate the stream to the peer (without sending), use the QUIC_STREAM_START_FLAG_IMMEDIATE stream start flag.

[nibanks]

Generally, apps don't want/need to indicate the stream immediately to the peer just because it was opened. So, MsQuic (by default) waits for application data to be queued before actually indicating anything to the peer. But that flag allows you to force the stream to be sent.

[AvatarGanymede]

I totally understand. Sincerely thanks!