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fix: correct ket{a} to ket{alpha} in Sec 1.1.6
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Chaps/Chap1.tex

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@@ -876,15 +876,15 @@ \subsection{基组变换}
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\subsection{本征值问题}
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\label{sec:1.1.6}
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算符$\op{O}$作用在一个矢量$\ket{a}$上,
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会得到一个新的矢量$\op{O}\ket{a}$
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算符$\op{O}$作用在一个矢量$\ket{\alpha}$上,
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会得到一个新的矢量$\op{O}\ket{\alpha}$
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通常情况下,这个新的矢量与原矢量不同。
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如果$\op{O}\ket{a}$$\ket{a}$只差一个常数,即:
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如果$\op{O}\ket{\alpha}$$\ket{\alpha}$只差一个常数,即:
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\begin{equation}
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\op{O}\ket{a} = \omega_{\alpha}\ket{a}
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\op{O}\ket{\alpha} = \omega_{\alpha}\ket{\alpha}
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\label{eq:1.72}
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\end{equation}
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这时,我们可以称$\ket{a}$为算符$\op{O}$关于\emph{本征值} $\omega_{\alpha}$\emph{本征矢量}。将本征矢归一化并不失普遍性:
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这时,我们可以称$\ket{\alpha}$为算符$\op{O}$关于\emph{本征值} $\omega_{\alpha}$\emph{本征矢量}。将本征矢归一化并不失普遍性:
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\begin{equation}
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\olp{\alpha}{\alpha} = 1
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\label{eq:1.73}
@@ -896,7 +896,7 @@ \subsection{本征值问题}
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\Mele{\alpha}{O}{\alpha} = \left\langle\alpha\middle\vert\op{O}^\dagger\middle\vert\alpha\right\rangle = {\Mele{\alpha}{O}{\alpha}}^\ast
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\label{eq:1.74}
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\end{equation}
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\autoref{eq:1.72}两边左乘$\bra{a}$,并带入\autoref{eq:1.74},我们得到:
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\autoref{eq:1.72}两边左乘$\bra{\alpha}$,并带入\autoref{eq:1.74},我们得到:
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\begin{equation}
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\omega_\alpha = \omega_\alpha^\ast
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\label{eq:1.75}

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