-
Notifications
You must be signed in to change notification settings - Fork 166
Open
Description
Here is some OSCAR code (for computing a recurrence relation, published by J-M Muller):
RR = real_field();
BIT_PREC = 233;
set_precision!(Balls, BIT_PREC);
Vprev = RR(2);
Vcurr = RR(-4);
Vprev += RR(2)^(1-div(75*BIT_PREC,100));
for i in 1:8+div(2*BIT_PREC,11)
Vnext = 111 - 1130/Vcurr + 3000/(Vcurr*Vprev);
Vprev = Vcurr;
Vcurr = Vnext;
println("Vcurr = $(Vcurr)");
end
The printed values of Vcurr include the following:
Vcurr = [6.2 +/- 0.0608]
Vcurr = [+/- 9.06]
Vcurr = [+/- 48.2]
Vcurr = [+/- 1.07e+2]
Vcurr = [1e+2 +/- 5.68]
Do the three central intervals contain zero or not? If they do, why do I not get a "division by zero" error?
OSCAR version: 1.7.0-DEV #master a3f6b0d 2025-12-10
Metadata
Metadata
Assignees
Labels
No labels