Fix Syntax Error in ID Comparison (Missing `==` in if statement) in Greenland Shark below the topic Integer Interning in Python

[M-Saneh]

Issue :
There's a syntax error in the code under the file/path: python/00_python_colab/02_data_types/.
Specifically, the comparison by ID is written as if(id(shark1_age) id(shark2_age)): which is missing ==.
It should be if (id(shark1_age) == id(shark2_age)): to work correctly.

Steps to Reproduce:

1. Open the Colab notebook here: https://colab.research.google.com/drive/1LqRMqVAff7jR_Xha7arxwHkFdQL08xAu?usp=sharing
2. Run the cell that contains the if(id(shark1_age) id(shark2_age)): line.
3. Observe the SyntaxError: invalid syntax. Perhaps you forgot a comma?

Expected Behavior:

• The code should compare the IDs of shark1_age and shark2_age without syntax errors.

Actual Behavior:

• The code fails to run due to a missing == operator in the if statement.

Suggested Fix:
Replace it with :

 if id(shark1_age) == id(shark2_age):

[M-Saneh]

I didn't understand your question , can you please elaborate?

…

On Mon, Apr 14, 2025 at 1:15 AM tanzeela-0325 ***@***.***> wrote: how to chack a use input — Reply to this email directly, view it on GitHub <#9 (comment)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/BKD523KTITPZBTWQB36CQST2ZLAU5AVCNFSM6AAAAABZJCI52WVHI2DSMVQWIX3LMV43OSLTON2WKQ3PNVWWK3TUHMZDQMBQGEYDMMJRGA> . You are receiving this because you authored the thread.Message ID: ***@***.***> *tanzeela-0325* left a comment (panaversity/learn-modern-ai-python#9) <#9 (comment)> how to chack a use input — Reply to this email directly, view it on GitHub <#9 (comment)>, or unsubscribe <https://github.com/notifications/unsubscribe-auth/BKD523KTITPZBTWQB36CQST2ZLAU5AVCNFSM6AAAAABZJCI52WVHI2DSMVQWIX3LMV43OSLTON2WKQ3PNVWWK3TUHMZDQMBQGEYDMMJRGA> . You are receiving this because you authored the thread.Message ID: ***@***.***>

[muskanBP]

Assalamualaikum:
Isko correct karne ke liye == operator ko sahi jagah lagana hoga. Aap id() ke values compare kar rahe ho, toh sahi syntax hoga:

if id(shark1_age) == id(shark2_age): # comparison by id

Full code:
shark1_age = 300
shark2_age = 300

print("Value of shark1_age = " + str(shark1_age) + ", and id(shark1_age) = " + str(id(shark1_age)))
print("Value of shark2_age = " + str(shark2_age) + ", and id(shark2_age) = " + str(id(shark2_age)))

if shark1_age == shark2_age: # comparison by value
print("shark1_age & shark2_age have same age")
else:
print("shark1_age & shark2_age have different age")

print(" ===================== ")

if id(shark1_age) == id(shark2_age): # comparison by id
print("shark1_age & shark2_age have same id")
else:
print("shark1_age & shark2_age have different id")