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docs/formulas/allowable-bearing-capacity.md

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# Bowles Allowable Bearing Capacity
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## Bowles Bearing Capacity for pad foundation
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$
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q_a(kPa) = 19.16(N_1)_{55} f_d\left(\dfrac{S}{25.4}\right),
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\ B \ \le \ 1.2m
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$
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$
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q_a(kPa) = 11.98(N_1)_{55}\left(\dfrac{3.28B + 1}{3.28B} \right)^2
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f_d \left(\dfrac{S}{25.4}\right), \ B \ \gt 1.2m
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$
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$f_d = 1 + 0.33 \cdot \dfrac{D_f}{B} \le 1.33$
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## Bowles Bearing Capacity for mat foundation
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$q_a(kPa) = 11.98(N_1)_{55}f_d\left(\dfrac{S}{25.4}\right)$
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$f_d = 1 + 0.33 \cdot \dfrac{D_f}{B} \le 1.33$
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# Allowable Bearing Capacity Formulas
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## Description of symbols used in bearing capacity equations
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| Symbol | Unit | Description |
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|--------|------|-----------------------------------|
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| $q_a$ | kPa | Allowable bearing capacity |
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| $N$ || Corrected SPT N-value |
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| $f_d$ || Depth factor |
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| $c_w$ || Water correction factor |
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| $S$ | mm | Tolerable settlement |
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| $B$ | m | Width of foundation footing |
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| $D_f$ | m | Depth of foundation footing |
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| $D_w$ | m | Depth of water below ground level |
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# Meyerhof Allowable Bearing Capacity
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## Meyerhof Bearing Capacity for pad foundation
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$
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q_a(kPa) = 12N f_d\left(\dfrac{S}{25.4}\right), \ B \ \le 1.2m
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$
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$
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q_a(kPa) = 8N\left(\dfrac{3.28B + 1}{3.28B} \right)^2 f_d\left(
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\dfrac{S}{25.4}\right), \ B \ \gt 1.2m
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$
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$f_d = 1 + 0.33 \cdot \dfrac{D_f}{B} \le 1.33$
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## Meyerhof Bearing Capacity for mat foundation
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$q_a(kPa) = 8 N f_d\left(\dfrac{S}{25.4}\right)$
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$f_d = 1 + 0.33 \cdot \dfrac{D_f}{B} \le 1.33$
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# Terzaghi Allowable Bearing Capacity
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## Terzaghi Bearing Capacity for pad foundation
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$
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q_a(kPa) = 12N \dfrac{1}{c_w f_d}\left(\dfrac{S}{25.4}\right),
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\ B \ \le 1.2m
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$
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$
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q_a(kPa) = 8N\left(\dfrac{3.28B + 1}{3.28B} \right)^2\dfrac{1}
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{c_w f_d}\left(\dfrac{S}{25.4}\right), \ B \ \gt 1.2m
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$
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$f_d = 1 + 0.25 \cdot \dfrac{D_f}{B} \le 1.25$
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$c_w = 2 - \dfrac{D_w}{2B} \le 2, D_w \gt D_f$
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$c_w = 2 - \dfrac{D_f}{2B} \le 2, D_w \le D_f$
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## Terzaghi Bearing Capacity for mat foundation
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$q_a(kPa) = 8N\dfrac{1}{c_w f_d}\left(\dfrac{S}{25.4}\right)$
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$f_d = 1 + 0.25 \cdot \dfrac{D_f}{B} \le 1.25$
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$c_w = 2 - \dfrac{D_w}{2B} \le 2, D_w \gt D_f$
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$c_w = 2 - \dfrac{D_f}{2B} \le 2, D_w \le D_f$

docs/formulas/index.md

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used in `geolysis`. Each explanation includes the formula, its variables, and
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a brief description of its application.
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- [Allowable Bearing Capacity](allowable-bearing-capacity.md)
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- [Ultimate Bearing Capacity](ultimate-bearing-capacity.md)
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- [Standard Penetration Test (SPT)](spt.md)
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- [Allowable Bearing Capacity](allowable-bearing-capacity/index.md)
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- [Ultimate Bearing Capacity](ultimate-bearing-capacity/index.md)
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- [Standard Penetration Test (SPT)](spt/index.md)

docs/formulas/spt.md

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# Dilatancy Corrections
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## Corrections
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$(N_1)_{60 \, (CORR)} = 15 + \dfrac{1}{2}((N_1)_{60} - 15) \, , \, (N_1)_{60} \gt 15$
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$(N_1)_{60 \, (CORR)} = (N_1)_{60} \, , \, (N_1)_{60} \le 15$
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docs/formulas/spt/index.md

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# SPT Formulas
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## Description of symbols used in SPT Corrections
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| Symbol | Description |
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|------------------------|----------------------------------------------------|
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| $(N_1)_{60}$ | SPT blow count corrected for overburden pressure |
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| $(N_1)_{60 \, (CORR)}$ | SPT blow count corrected for dilatancy |
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| $N_{60}$ | SPT blow count corrected for 60% hammer efficiency |
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| $C_N$ | Overburden pressure correction factor |
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| $\sigma_o$ | Effective overburden pressure at the test depth |
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# Overburden Pressure Corrections
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$(N_1)_{60} = C_N \cdot N_{60}$
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$C_N \le 2$
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!!! note
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`60` is used in this case to represent `60%` hammer
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efficiency and can be any percentage of hammer efficiency
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e.g. $N_{55}$ for `55%` hammer efficiency.
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## Gibbs & Holtz (1957)
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$C_N = \dfrac{350}{\sigma_o + 70} \, \sigma_o \le 280kN/m^2$
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!!! note
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$\frac{N_c}{N_{60}}$ should lie between 0.45 and 2.0, if
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$\frac{N_c}{N_{60}}$ is greater than 2.0, :math:`N_c` should be
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divided by 2.0 to obtain the design value used in finding the
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bearing capacity of the soil.
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## Peck and Bazaraa (1969)
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$
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C_N = \dfrac{4}{1 + 0.0418 \cdot \sigma_o}, \,
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\sigma_o \lt 71.8kN/m^2
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$
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$
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C_N = \dfrac{4}{3.25 + 0.0104 \cdot \sigma_o},
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\, \sigma_o \gt 71.8kN/m^2
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$
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$C_N = 1 \, , \, \sigma_o = 71.8kN/m^2$
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## Peck et al. (1974)
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$C_N = 0.77 \log \left(\dfrac{2000}{\sigma_o} \right)$
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## Liao & Whitman (1986)
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$C_N = \sqrt{\dfrac{100}{\sigma_o}}$
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## Skemton (1986)
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$C_N = \dfrac{2}{1 + 0.01044 \cdot \sigma_o}$

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