P-25.c

//Write a program in c to solve all the algebraic identities.
#include<stdio.h>
int main()
{
float a,b,c;
printf("Enter the values of A,B and C:\n");
scanf("%f%f%f",&a,&b,&c);
float s1,s2,s3,s4,s5,s6,s7,s8,s9,s10,s11,s12,s13;
s1=(a*a)+(2*a*b)+(b*b);
s2=(a*a)-(2*a*b)+(b*b);
s3=(a+b)*(a-b);
s4=(a*a)+(b*b)+(c*c)+(2*a*b)+(2*b*c)+(2*c*a);
s5=(a*a)+(b*b)+(c*c)+(2*a*b)-(2*b*c)-(2*c*a);
s6=(a*a)+(b*b)+(c*c)-(2*a*b)-(2*b*c)+(2*c*a);
s7=(a*a)+(b*b)+(c*c)-(2*a*b)+(2*b*c)-(2*c*a);
s8=(a*a)+(b*b)+(c*c)-(2*a*b)+(2*b*c)-(2*c*a);
s9=(a*a*a)+(b*b*b)+((3*a*b)+(a+b));
s10=(a*a*a)-(b*b*b)-((3*a*b)+(a-b));
s11=(a+b)*((a*a)-(a*b)+(b*b));
s12=(a-b)*((a*a)+(a*b)+(b*b));
s13=(a*a*a)+(b*b*b)+(c*c*c)-(3*a*b*c);
printf("S_1=%f\n",s1);
printf("S_2=%f\n",s2);
printf("S_3=%f\n",s3);
printf("S_4=%f\n",s4);
printf("S_5=%f\n",s5);
printf("S_6=%f\n",s6);
printf("S_7=%f\n",s7);
printf("S_8=%f\n",s8);
printf("S_9=%f\n",s9);
printf("S_10=%f\n",s10);
printf("S_11=%f\n",s11);
printf("S_12=%f\n",s12);
printf("S_13=%f\n",s13);
}