[@overload]: What is the effect of the *implementation* type-signature? #1840
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Description
One thing that I've found underspecified when using @overload
is what the type signature of the actual function should be.
For example, let's say I have a function like:
from typing import overload, Literal
@overload
def f(x: int, z: Literal[True]) -> str: ...
@overload
def f(x: int, z: Literal[False] = ...) -> int: ...
def f(x: int, z: bool = False) -> str | int:
if z:
return "hello"
return 1
What is the effect of the last line? In particular:
- The documentation and examples often just use no annotations for the implementation signature (
def f(x, z):
). Is that the right thing to do (I sometimes getOverloaded implementation is not consistent with signature of overload 1
errors if I leave out the type annotations)? - If I do specify types on the last, do I also have to add it to
@overload
list -- in other words:
@overload
def f(x: int, z: Literal[True]) -> str: ...
@overload
def f(x: int, z: Literal[False] = ...) -> int: ...
@overload
def f(x: int, z: bool = ...) -> str | int # is this overload necessary?
def f(x: int, z: bool = False) -> str | int:
if z:
return "hello"
return 1
Both pyright and mypy seem to interpret things differently with and without it (e.g. see this play link).
I understand that @overload
is a complicated feature, but I'm hoping this is a small corner we can start with.