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In mathematics, **Euler’s identity** (also known as _Euler’s
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equation_) is the equality
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$$ e^(i pi) + 1 = 0 $$
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where
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- $e$ is Euler's number, the base of natural logarithms,
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- $i$ is the imaginary unit, which by definition satisfies $i^2 = -1$,
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and
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- $pi$ is pi, the ratio of the circumference of a circle to its
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diameter.
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Euler’s identity is named after the Swiss mathematician Leonhard
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Euler. It is a special case of Euler’s formula $e^(ix) = cos x + i sin
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x$ when evaluated for $x=pi$. Euler's identity is considered an
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exemplar of mathematical beauty, as it shows a profound connection
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between the most fundamental numbers in mathematics. In addition, it
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is directly used in a proof that $pi$ is transcendental, which implies
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the impossibility of squaring the circle.
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## Imaginary exponents
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Euler’s identity asserts that $e^(i pi)$ is equal to $-1$. The
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expression $e^(i pi)$ is a special case of the expression $e^z$, where
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$z$ is any complex number. In general, $e^z$ is defined for complex $z$
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by extending one of the definitions of the exponential function from
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real exponents to complex exponents. For example, one common
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definition is:
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$$
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e^z = lim_(n->oo) (1 + z/n)^n.
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$$
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Euler’s identity therefore states that the limit, as $n$ approaches
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infinity, of $(1 + (i pi)/n)^n$ is equal to $-1$.
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Euler’s identity is a special case of Euler’s formula, which states
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that for any real number $x$,
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$$ e^(ix) = cos x + i sin x $$
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where the inputs of the trigonometric functions sine and cosine are
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given in radians.
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In particular, when $x = pi$,
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$$
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e^(i pi) = cos pi + i sin pi.
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$$
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Since
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$$ cos pi = -1 $$
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and
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$$ sin pi = 0 $$
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it follows that
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$$ e^(i pi) = -1 + 0i, $$
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which yields Euler's identity:
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$$ e^(i pi) + 1 = 0. $$
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## Generalizations
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Euler’s identity is also a special case of the more general identity
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that the $n$th roots of unity, for $n > 1$, add up to $0$:
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$$
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sum_(k=0)^(n-1) e^(2pi i k/n) = 0 .
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$$
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Euler’s identity is the case where $n = 2$.
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A similar identity also applies to quaternion exponential: let ${i, j,
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k}$ be the basis quaternions; then,
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$$
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e^(1/sqrt(3) (i +- j +- k) pi) + 1 = 0 .
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$$
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More generally, let q be a quaternion with a zero real part and a norm
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equal to $1$; that is, $q = ai + bj + ck$, with $a^2 + b^2 + c^2 =
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1$. Then one has
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$$
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e^(q pi) + 1 = 0 .
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$$
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The same formula applies to octonions, with a zero real part and a
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norm equal to $1$. These formulas are a direct generalization of
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Euler’s identity, since $i$ and $-i$ are the only complex numbers with
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a zero real part and a norm (absolute value) equal to $1$.
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