Help with addressing devices.

[0Zeyrox0]

Can someone tell me or give me an example code how I can re-address a device (e.g. a lamp)?

[sde1000]

If a device already has a short address that you know, and you just want to change it to a different address, you can use dali.gear.SetShortAddress(), eg. to change a lamp from address 5 to address 10 you would send:

dali.gear.DTR0(10)
dali.gear.SetShortAddress(5)

If it's the only device on the bus you could send SetShortAddress as a broadcast. Don't do this if there is more than one device, they will all send up with the same address!

dali.gear.DTR0(10)
dali.gear.SetShortAddress(dali.address.GearBroadcast())

If you have multiple devices to assign addresses to, you would use dali.sequences.Commissioning().

Obviously the details of how you send these commands on the bus depend on the type of interface that you are using.

[0Zeyrox0]

I'm using a Lunatone RS232 LUBA interface.

[0Zeyrox0]

And how would it work with the sequence (dali.sequences.Commissioning()) if I wanted to change the address of 3 lamps, for example?

[sde1000]

By default the Commissioning() sequence will assign a short address to any gear that doesn't have one. If you use Commissioning(readdress=True) then it will assign a fresh short address to all gear, starting at 0, and in a random order. (You can then discover which device has received which address by, for example, turning the lamp at that address on and off.)

[sde1000]

Have you managed to get the LUBA interface working? Have a look at examples/async-serial-luba.py for an example of how to use it, which you can build on to do whatever you need to do.

[0Zeyrox0]

Yes, the example helped me a lot and it works with the interface I have.

[0Zeyrox0]

I have the problem that when I address the devices, I can only find half of them after addressing.

This is the code I used for addressing:

async def assign_addresses(self, mapping):
        print("Starte Adresszuweisung absteigend sortiert")
        assigned = 0
        sorted_mapping = sorted(mapping, key=lambda x: x[0], reverse=True)
        for new_addr, old_addr, _ in sorted_mapping:
            if new_addr != old_addr:
                try:
                    await self.driver.send(DTR0(new_addr))
                    await asyncio.sleep(0.1)
                    await self.driver.send(SetShortAddress(old_addr))
                    print(f"Adresse {old_addr} geändert zu {new_addr}")
                    assigned += 1
                    await asyncio.sleep(0.4)
                except Exception as e:
                    print(f"Fehler bei Adresszuweisung {old_addr} → {new_addr}: {e}")
        print(f"Adresszuweisung abgeschlossen ({assigned} Änderungen durchgeführt)")

[sde1000]

What mapping are you passing in? How many devices are there?

You have to be careful when reassigning addresses in this way that you never set two devices to have the same address at the same time.

[0Zeyrox0]

This is the mapping (New address, Old address, Group):
Mapping für Adressierung: [(1, 0, 0), (2, 1, 0), (3, 2, 0), (4, 3, 0), (5, 4, 0), (6, 5, 0), (7, 6, 0), (8, 7, 0), (9, 8, 0), (10, 9, 0), (11, 10, 0), (12, 11, 0), (13, 12, 0), (14, 13, 0), (15, 14, 0), (16, 15, 0), (17, 16, 0), (18, 17, 0), (19, 18, 0), (20, 19, 0), (21, 20, 0), (22, 21, 0), (23, 22, 0), (24, 23, 0), (25, 24, 0), (26, 25, 0), (27, 26, 0), (28, 27, 0), (29, 28, 0), (30, 29, 0), (31, 30, 0), (32, 31, 0)]

The group is not yet in use.
There are as many devices as were found on the bus route. In this case, 32 devices.

Yes, I already thought so. That's why I only worked with this mapping for now, starting with the largest new address.

[sde1000]

Aha. I've realised what it is! My advice at the start of the discussion was not actually correct.

The comment for SetShortAddress() says the following:

class SetShortAddress(_StandardCommand):
    """Save the value in DTR0 as the new short address.

    The DTR must contain either:
    - (address<<1)|1 (i.e. 0AAAAAA1) to set a short address
    - 255 (i.e. 11111111) to remove the short address
    """
    _cmdval = 0x80
    uses_dtr0 = True
    sendtwice = True

So instead of sending DTR0(new_address) you should be sending DTR0((new_address << 1) | 1)

Apologies for the bad advice.

[0Zeyrox0]

I'm currently learning Python. What does (new address << 1) | 1) do?

[sde1000]

It shifts new_address one bit to the left, and then bitwise ORs it with 1.

So if you start with 00xxxxxx as new_address, you will end up with 0xxxxxx1 in DTR0.

I had forgotten that this was necessary to use SetShortAddress() when I wrote my original answer.

[0Zeyrox0]

You're a great help to me. Thank you.