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Get pixel position from 2theta and azimuth ? #2480

Answered by kif
smerkel asked this question in Q&A
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Hi Sebastien,

There is no "direct" way to perform this, but approximate solutions based on InvertGeometry which is based on on linear interpolation. There is an example of usage in the test suite.

You can also refer to the issue #1354
Cheers,

Jerome

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