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baekjoon_16637.cpp
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75 lines (66 loc) · 1.42 KB
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#include <iostream>
#include <cstdio>
#include <climits>
using namespace std;
char arr[20];
int max_cal = INT_MIN;
void sol(int n, int idx, int cal){
int yes, no;
yes = arr[idx]-'0';
no = cal;
if (idx > n - 1)
{
max_cal = max(max_cal, cal);
//printf("%d\n", max_cal);
return ;
}
//괄호 O
if (idx + 2 < n)
{
if(arr[idx+1] == '+'){
yes += (arr[idx+2]-'0');
}
else if(arr[idx+1] == '-'){
yes -= (arr[idx+2]-'0');
}
else if(arr[idx+1] == '*'){
yes *= (arr[idx+2]-'0');
}
if(idx!=0){
if(arr[idx-1] == '+'){
cal += yes;
}
else if(arr[idx-1] == '-'){
cal -= yes;
}
else if(arr[idx-1] == '*'){
cal *= yes;
}
}
else{
cal = yes;
}
sol(n, idx + 4, cal);
}
if(idx!=0){
if(arr[idx-1] == '+'){
no += (arr[idx]-'0');
}
else if(arr[idx-1] == '-'){
no -= (arr[idx]-'0');
}
else if(arr[idx-1] == '*'){
no *= (arr[idx]-'0');
}
}
else
no = (arr[idx]-'0');
sol(n, idx + 2, no);
}
int main(void){
int n;
scanf("%d", &n);
scanf("%s", arr);
sol(n, 0, 0);
printf("%d\n", max_cal);
}