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queue-using-stacks.py
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42 lines (31 loc) · 1.07 KB
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# Problem: Implement Queue using Stacks
# Time Complexity:
# push: O(1) - always
# pop: O(1) amortized - O(n) only when outStack is empty, but each element moved once in its lifetime
# peek: O(1) amortized - same reasoning as pop
# empty: O(1) - always
# Space Complexity: O(n) where n is number of elements in the queue
# Did this code successfully run on Leetcode: YES
# Any problem you faced while coding this: No
class MyQueue(object):
def __init__(self):
self.inStack = []
self.outStack = []
def push(self, x):
self.inStack.append(x)
def pop(self):
self.peek()
return self.outStack.pop()
def peek(self):
if len(self.outStack) == 0:
while len(self.inStack) > 0:
self.outStack.append(self.inStack.pop())
return self.outStack[-1]
def empty(self):
return len(self.inStack) == 0 and len(self.outStack) == 0
# Your MyQueue object will be instantiated and called as such:
# obj = MyQueue()
# obj.push(x)
# param_2 = obj.pop()
# param_3 = obj.peek()
# param_4 = obj.empty()