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Syntax extensions for Parallel require Monad[M], but implementation doesn't #2254

@oleg-py

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@oleg-py

I discovered today that to use syntax extension for parTraverse/parSequence, a Monad[M] instance is required.

final class ParallelTraversableOps[T[_], A](val ta: T[A]) extends AnyVal {

  def parTraverse[M[_]: Monad, F[_], B]
  (f: A => M[B])(implicit T: Traverse[T], P: Parallel[M, F]): M[T[B]] =
    Parallel.parTraverse(ta)(f)

}

While Parallel.parTraverse is defined as follows (notice lack of Monad[M])

  def parTraverse[T[_]: Traverse, M[_], F[_], A, B]
  (ta: T[A])(f: A => M[B])(implicit P: Parallel[M, F]): M[T[B]] = {
    val gtb: F[T[B]] = Traverse[T].traverse(ta)(f andThen P.parallel.apply)(P.applicative)
    P.sequential(gtb)
  }

Same is true for parSequence. Is that an oversight?

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