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spec/index.html
@@ -1959,11 +1959,7 @@ <h2>Proofs of some results</h2>
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<p>Using the terminology in the previous proof: if H does not contain any skolem IRIs, then H=ks(H).
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So if sk(G) entails H then G entails ks(H)=H; and if G entails H then sk(G) entails G entails H, so sk(G) entails H. QED.</p>
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<p class="fact"><b>Subgraph Lemma</b>.
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A graph S simply entails each of its its subgraphs E.</p>
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