README.md

612. 平面上的最近距离

English Version

题目描述

None

解法

SQL

SELECT round(min(sqrt(power(p1.x-p2.x,
        2) + power(p1.y-p2.y,
        2))),
        2) shortest
FROM point_2d p1, point_2d p2
WHERE (p1.x, p1.y) <> (p2.x,p2.y)